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A260986
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Numbers n such that H(n)/H(n^2) is a new record, where H(n) = A000120(n) is the sum of the binary digits of n.
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1
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1, 23, 111, 479, 1471, 6015, 24319, 28415, 490495, 6025215, 8122367, 98549759, 132104191, 1593769983, 1862205439, 29930291199, 479961546751, 514321285119, 8237743079423, 131872659079167, 136270705590271, 35461448750596095, 7998111458938322943, 9151032963545169919
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OFFSET
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1,2
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COMMENTS
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This sequence is infinite, a result which follows from Stolarsky's Theorem 2.
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LINKS
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EXAMPLE
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23 is 10111 in binary and 23^2 = 529 is 1000010001 in binary. Each smaller number has H(n)/H(n^2) <= 1, but H(23)/H(529) = 4/3 > 1, so 23 is in this sequence.
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MATHEMATICA
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DeleteDuplicates[Table[{n, Total[IntegerDigits[n, 2]]/Total[IntegerDigits[n^2, 2]]}, {n, 500000}], GreaterEqual[ #1[[2]], #2[[2]]]&][[;; , 1]] (* The program generates the first 9 terms of the sequence. *) (* Harvey P. Dale, Sep 21 2023 *)
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PROG
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(PARI) r=2; forstep(n=1, 1e9, 2, t=hammingweight(n^2)/hammingweight(n); if(t<r, r=t; print1(n", ")))
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CROSSREFS
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KEYWORD
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base,nonn
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AUTHOR
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EXTENSIONS
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STATUS
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approved
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