A260715 Row 5 of A260717.

11, 13, 17, 23, 25, 29, 37, 41, 43, 47, 53, 55, 61, 67, 71, 73, 77, 83, 89, 91, 97, 101, 103, 107, 115, 119, 121, 127, 131, 133, 143, 145, 149, 151, 157, 161, 167, 173, 175, 179, 181, 187, 193, 197, 203, 205, 209, 211, 221, 223, 227, 233, 235, 239, 247, 251, 253, 257, 263, 265, 271, 277, 281, 283, 287, 293, 299, 301, 307, 311, 313

Offset

1,1

Links

Antti Karttunen, Table of n, a(n) for n = 1..10000

Index entries for linear recurrences with constant coefficients, signature (1, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1, -1).

Formula

Other identities. For all n >= 1:

a(1+(11*(n-1))) = A255415(n).

a(n) ~ 35*n/8. - Charles R Greathouse IV, May 31 2026

Prog

(Scheme) (define (A260715 n) (A260717bi 5 n)) ;; A260717bi given in A260717.
(PARI) a(n)=(35*n+8726068698479420916885430980594001581964119039078101159083379619613970440433642628\52^(n%48)%52+8)/8 \\ Charles R Greathouse IV, May 31 2026

Crossrefs

Row 5 of A260717.

Setwise difference of A260714 \ A255414.

Cf. A255415 (only every eleventh term of this sequence, starting from 11).

Differs from A003309(n+5) for the first time at n=12, as a(12) = 55, the first nonludic number to be removed at stage 5 of the sieve, which is missing from A003309.

Sequence in context: A036979 A036977 A120168 * A087681 A137669 A360979

Adjacent sequences: A260712 A260713 A260714 * A260716 A260717 A260718

Keyword

nonn,easy,changed

Author

Antti Karttunen, Jul 30 2015

Status

approved