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A260190
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Kronecker symbol(-6 / 2*n + 1).
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4
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1, 0, 1, 1, 0, 1, -1, 0, -1, -1, 0, -1, 1, 0, 1, 1, 0, 1, -1, 0, -1, -1, 0, -1, 1, 0, 1, 1, 0, 1, -1, 0, -1, -1, 0, -1, 1, 0, 1, 1, 0, 1, -1, 0, -1, -1, 0, -1, 1, 0, 1, 1, 0, 1, -1, 0, -1, -1, 0, -1, 1, 0, 1, 1, 0, 1, -1, 0, -1, -1, 0, -1, 1, 0, 1, 1, 0, 1
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OFFSET
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0
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LINKS
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FORMULA
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Euler transform of length 12 sequence [ 0, 1, 1, -1, 0, -2, 0, 0, 0, 0, 0, 1].
G.f.: (1 + x^3) / (1 - x^2 + x^4).
G.f.: 1 / (1 - x^2 / (1 - x / (1 + 2*x / ( 1 - x / (1 - x / (1 + x)))))).
a(n) = (-1)^n * a(n+3) = -a(n+6) = a(5-n) = a(n+2) - a(n+4) for all n in Z.
a(2*n) = A010892(n). a(3*n + 1) = 0. a(3*n) = a(3*n + 2) = A057077(n).
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EXAMPLE
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G.f. = 1 + x^2 + x^3 + x^5 - x^6 - x^8 - x^9 - x^11 + x^12 + x^14 + x^15 + ...
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MATHEMATICA
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a[ n_] := KroneckerSymbol[ -6, 2 n + 1];
LinearRecurrence[{0, 1, 0, -1}, {1, 0, 1, 1}, 120] (* Harvey P. Dale, Jun 24 2018 *)
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PROG
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(PARI) {a(n) = kronecker( -6, 2*n + 1)};
(PARI) {a(n) = (-1)^(n\6) * [ 1, 0, 1][n%3 + 1]};
(PARI) {a(n) = if( n<3, n=5-n); polcoeff( (1 + x^3) / (1 - x^2 + x^4) + x * O(x^n), n)};
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CROSSREFS
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KEYWORD
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sign,easy
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AUTHOR
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STATUS
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approved
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