

A257987


Sequence (a(n)) generated by Rule 3 (in Comments) with a(1) = 2 and d(1) = 2.


2



2, 3, 6, 4, 8, 5, 10, 9, 17, 7, 13, 25, 11, 21, 12, 23, 15, 29, 14, 27, 16, 31, 18, 35, 19, 37, 20, 39, 32, 26, 22, 43, 24, 47, 42, 30, 59, 28, 55, 33, 65, 36, 71, 34, 67, 40, 79, 38, 75, 41, 81, 45, 89, 44, 87, 48, 95, 46, 91, 49, 97, 50, 99, 51, 101, 57
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OFFSET

1,1


COMMENTS

Rule 3 follows. For k >= 1, let A(k) = {a(1), …, a(k)} and D(k) = {d(1), …, d(k)}. Begin with k = 1 and nonnegative integers a(1) and d(1).
Step 1: If there is an integer h such that 1  a(k) < h < 0 and h is not in D(k) and a(k) + h is not in A(k), let d(k+1) be the least such h, let a(k+1) = a(k) + h, replace k by k + 1, and repeat Step 1; otherwise do Step 2.
Step 2: Let h be the least positive integer not in D(k) such that a(k)  h is not in A(k). Let a(k+1) = a(k) + h and d(k+1) = h. Replace k by k+1 and do Step 1.
See A257905 for a guide to related sequences and conjectures.


LINKS

Clark Kimberling, Table of n, a(n) for n = 1..1000


FORMULA

a(n)  a(n1) = A257984(n) for n >= 2.


EXAMPLE

a(1) = 2, d(1) = 2;
a(2) = 3, d(2) = 1;
a(3) = 6, d(3) = 3;
a(4) = 4, d(4) = 2.


MATHEMATICA

{a, f} = {{2}, {2}}; Do[tmp = {#, #  Last[a]} &[Min[Complement[#, Intersection[a, #]]&[Last[a] + Complement[#, Intersection[f, #]] &[Range[2  Last[a], 1]]]]];
If[! IntegerQ[tmp[[1]]], tmp = {Last[a] + #, #} &[NestWhile[# + 1 &, 1, ! (! MemberQ[f, #] && ! MemberQ[a, Last[a]  #]) &]]]; AppendTo[a, tmp[[1]]]; AppendTo[f, tmp[[2]]], {120}]; {a, f} (* Peter J. C. Moses, May 14 2015 *)


CROSSREFS

Cf. A257905, A257909.
Sequence in context: A154285 A258078 A036552 * A132169 A273666 A302023
Adjacent sequences: A257984 A257985 A257986 * A257988 A257989 A257990


KEYWORD

nonn,easy


AUTHOR

Clark Kimberling, Jun 02 2015


STATUS

approved



