A256500 Decimal expansion of the positive solution to x = 2*(1-exp(-x)).

1, 5, 9, 3, 6, 2, 4, 2, 6, 0, 0, 4, 0, 0, 4, 0, 0, 9, 2, 3, 2, 3, 0, 4, 1, 8, 7, 5, 8, 7, 5, 1, 6, 0, 2, 4, 1, 7, 8, 9, 0, 0, 2, 4, 2, 4, 8, 1, 8, 8, 5, 9, 3, 6, 4, 9, 9, 9, 5, 0, 4, 5, 1, 1, 6, 9, 6, 0, 8, 4, 9, 8, 4, 8, 1, 6, 1, 8, 7, 9, 5, 0, 2, 3, 2, 7, 4, 9, 9, 2, 7, 6, 6, 1, 8, 4, 4, 0, 7, 1, 4, 1, 7, 0, 6

Offset

1,2

Comments

Each of the positive solutions to x = q*(1-exp(-x)) obtained for q = 2, 3, 4, and 5, appears in several formulas pertinent to Planck's black-body radiation law. For a given q, the solution can be also written as q+W(-q/exp(q)), where W is the Lambert function. Here q = 2.

The constant appears in asymptotic formula for A007820. - Vladimir Reshetnikov, Oct 10 2016

Links

Stanislav Sykora, Table of n, a(n) for n = 1..2000

V. Kotesovec, Non-attacking chess pieces, 6ed, 2013, p. 249.

SpectralCalc, Calculation of Blackbody Radiance, Appendix C.

Wikipedia, Planck's law

Index entries for transcendental numbers

Example

1.5936242600400400923230418758751602417890024248188593649995...

Mathematica

RealDigits[2 + LambertW[-2 Exp[-2]], 10, 100][[1]] (* Vladimir Reshetnikov, Oct 10 2016 *)

Prog

(PARI) a2=solve(x=0.1, 10, x-2*(1-exp(-x))) \\ Use real precision in excess

Crossrefs

Cf. A194567 (q=3), A256501 (q=4), A256502 (q=5).

Cf. A191236, A217905.

Sequence in context: A021948 A306883 A333155 * A239545 A228402 A154265

Adjacent sequences: A256497 A256498 A256499 * A256501 A256502 A256503

Keyword

nonn,cons,changed

Author

Stanislav Sykora, Mar 31 2015

Status

approved