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A256293
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Apply the transformation 0 -> 1 -> 2 -> 0 to the digits of n written in base 3, then convert back to base 10.
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8
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1, 2, 0, 7, 8, 6, 1, 2, 0, 22, 23, 21, 25, 26, 24, 19, 20, 18, 4, 5, 3, 7, 8, 6, 1, 2, 0, 67, 68, 66, 70, 71, 69, 64, 65, 63, 76, 77, 75, 79, 80, 78, 73, 74, 72, 58, 59, 57, 61, 62, 60, 55, 56, 54, 13, 14, 12, 16, 17, 15
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OFFSET
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0,2
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COMMENTS
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See A256294 - A256299 for bases 4 through 9, and A256303 for the variant where the result is not converted back to base 10.
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LINKS
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EXAMPLE
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a(3) = 7 because 3 = 10[3] becomes 21[3] = 7.
a(8) = 0 because 8 = 22[3] becomes 00[3] = 0.
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MATHEMATICA
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Table[FromDigits[IntegerDigits[n, 3]/.{0->1, 1->2, 2->0}, 3], {n, 0, 100}] (* Harvey P. Dale, Jan 21 2019 *)
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PROG
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(PARI) A256293(n, b=3)=!n+apply(t->(t+1)%b, n=digits(n, b))*vector(#n, i, b^(#n-i))~
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CROSSREFS
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KEYWORD
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nonn,base,easy
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AUTHOR
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STATUS
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approved
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