OFFSET
1,1
COMMENTS
Let the edge lengths of the triangle be 2x-1, 2x, 2x+1 so that area = sqrt{3x * x * (x-1) * (x+1)} and we need x^2 - 1 to be of shape 3y^2. That is, x/y is an even rank convergent to the continued fraction of sqrt(3) and x is A001075.
The intermediate length sides are given by A003500(n), n >= 1. Note that A003500(0) = 2 corresponds to the degenerate (Heronian) triangle with sides {1, 2, 3} and area 0. - Daniel Forgues, May 28 2014
REFERENCES
Nakane Genkei (Nakane the Elder), Shichijo Beki Yenshiki, 1691.
LINKS
Harvey P. Dale, Table of n, a(n) for n = 1..1000
David Eugene Smith and Yoshio Mikami, A history of Japanese mathematics, Dover, 2004, p. 168.
Index entries for linear recurrences with constant coefficients, signature (-1,-1,4,4,4,-1,-1,-1).
FORMULA
G.f.: (-3*x^7 - 5*x^6 - 6*x^5 + 4*x^4 + 10*x^3 + 12*x^2 + 7*x + 3)/ ((1+x+x^2)*(1-4*x^3+x^6)). - R. J. Mathar, May 30 2023
MATHEMATICA
LinearRecurrence[{-1, -1, 4, 4, 4, -1, -1, -1}, {3, 4, 5, 13, 14, 15, 51, 52}, 40] (* Harvey P. Dale, May 04 2021 *)
PROG
(PARI) Vec((-3*x^7 - 5*x^6 - 6*x^5 + 4*x^4 + 10*x^3 + 12*x^2 + 7*x + 3)/(x^8 + x^7+ x^6 - 4*x^5 - 4*x^4 - 4*x^3 + x^2 + x + 1)+O(x^99))
CROSSREFS
KEYWORD
nonn,easy
AUTHOR
R. K. Guy and Charles R Greathouse IV, May 16 2014
STATUS
approved
