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A233543
Table T(n,m) = m! read by rows.
0
1, 1, 1, 1, 1, 2, 1, 1, 2, 6, 1, 1, 2, 6, 24, 1, 1, 2, 6, 24, 120, 1, 1, 2, 6, 24, 120, 720, 1, 1, 2, 6, 24, 120, 720, 5040, 1, 1, 2, 6, 24, 120, 720, 5040, 40320, 1, 1, 2, 6, 24, 120, 720, 5040, 40320, 362880
OFFSET
0,6
COMMENTS
Consider the triangle A193738(n)
1,
1, 1,
1, 2, 2,
1, 2, 3, 3,
1, 2, 3, 4, 4,
1, 2, 3, 4, 5, 5,
1, 2, 3, 4, 5, 6, 6, etc.
The main diagonal is A028310.
The first column of the inverse triangle is
1, -1, 1/2, -1/6, 1/24, -1/120, -1/720,... = 1/e, where e is Euler's number A001113. It is found by
1,
1 - 1 = 0,
1 - 2 + 2/2 = 0,
1 - 2 + 3/2 - 3/6 = 0,
1 - 2 + 3/2 - 4/6 + 4/24 = 0,
1 - 2 + 3/2 - 4/6 + 5/24 - 5/120 = 0,
1 - 2 + 3/2 - 4/6 + 5/24 - 6/120 + 6/720 = 0, etc.
The numerators of this fractional triangle are A193738 signed by rows.
The denominators are a(n).
The denominators of the inverse of A193738(n) are A213936.
FORMULA
T(n,m) = A000142(m).
EXAMPLE
1,
1, 1,
1, 1, 2,
1, 1, 2, 6
1, 1, 2, 6, 24,
1, 1, 2, 6, 24, 120, etc.
MATHEMATICA
t[_, m_] := m!; Table[Table[t[n, m], {m, 0, n}], {n, 0, 9}] // Flatten (* Jean-François Alcover, Dec 12 2013 *)
CROSSREFS
Cf. A166350.
Sequence in context: A246660 A346422 A245405 * A156588 A278543 A374571
KEYWORD
nonn,frac,tabl,less
AUTHOR
Paul Curtz, Dec 12 2013
STATUS
approved