1,2

Conjecture: a(n) > 0 for all n. Equivalently, any number not divisible by 4 divides infinitely many members of A232637.

Charles R Greathouse IV, Table of n, a(n) for n = 1..10000

(PARI) ok(n)=hammingweight(n)%2 && hammingweight(n\2+1)%2

a(n)=my(k=n+(n-1)\3, m=k); while(!ok(m), m+=k); (m+6)\4 \\ Charles R Greathouse IV, Dec 09 2013

Cf. A232637, A000069, A042968.

Sequence in context: A051678 A079906 A226814 * A189327 A217575 A172154

Adjacent sequences: A233416 A233417 A233418 * A233420 A233421 A233422

nonn

Charles R Greathouse IV, Dec 09 2013

approved