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A230304
a(n) = 10^( (10^n-1)/9 + n) + 1.
0
101, 10000000000001, 1000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000001
OFFSET
1,1
COMMENTS
Makowski observes that A230093(a(n)) >= 2 for all n >= 1.
REFERENCES
Makowski, Andrzej. On Kaprekar's "junction numbers''. Math. Student 34 1966 77 (1967). MR0223292 (36 #6340)
CROSSREFS
KEYWORD
nonn,base
AUTHOR
N. J. A. Sloane, Oct 26 2013
STATUS
approved