OFFSET
0,5
COMMENTS
The order of the primes in the prime factorization of a(n) is given by
ord_{p}(a(n)) = (1/4)*Sum_{i>=1} floor(n/p^i)*(floor(n/p^i)-1) + (1/2)*Sum_{i>=1} floor(floor(n/2)/p^i).
For n > 1: a(n) = a(n-1) if and only if n is prime.
MAPLE
PROG
CROSSREFS
KEYWORD
nonn
AUTHOR
Peter Luschny, Apr 08 2013
STATUS
approved