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A222206
Least prime p such that q^(p-1) == 1 (mod p^2) for n primes q < p.
2
2, 11, 349, 13691, 24329
OFFSET
0,1
COMMENTS
I found no new terms < 5*10^6. - J. Stauduhar, Mar 23 2013
a(5) > 13*10^6, if it exists. Note that, up to 13*10^6, the only other prime p (apart 24329) such that the congruence is satisfied for 4 primes q < p is 9656869. - Giovanni Resta, May 23 2017
REFERENCES
L. E. Dickson, History of the Theory of Numbers, vol. 1, chap. IV.
LINKS
W. Keller and J. Richstein, Fermat quotients that are divisible by p. [Broken link]
Wilfrid Keller and Jörg Richstein, Solutions of the congruence a^(p-1) == 1 (mod (p^r)), Math. Comp. 74 (2005), 927-936.
EXAMPLE
For the prime p = 349, but for no smaller prime, there are 2 primes q = 223 and 317 < p with q^(p-1) == 1 (mod p^2), so a(2) = 349.
MATHEMATICA
f[n_] := Block[{p = 2, q = {}}, While[ Count[ PowerMod[ q, p - 1, p^2], 1] != n, q = Join[q, {p}]; p = NextPrime@ p]; p]; Array[f, 5, 0] (* Robert G. Wilson v, Mar 09 2015 *)
PROG
(PARI) a(n) = {nb = 0; p = 2; while (nb != n, p = nextprime(p+1); nb = 0; forprime(q=2, p-1, if (Mod(q, p^2)^(p-1) == 1, nb ++); if (nb > n, break); ); ); p; } \\ Michel Marcus, Mar 08 2015
CROSSREFS
KEYWORD
nonn,more
AUTHOR
Jonathan Sondow, Feb 12 2013
STATUS
approved