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A221877
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Number of order-preserving or order-reversing full contraction mappings (of an n-chain) with height exactly k.
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6
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1, 2, 2, 3, 8, 2, 4, 18, 12, 2, 5, 32, 36, 16, 2, 6, 50, 80, 60, 20, 2, 7, 72, 150, 160, 90, 24, 2, 8, 98, 252, 350, 280, 126, 28, 2, 9, 128, 392, 672, 700, 448, 168, 32, 2, 10, 162, 576, 1176, 1512, 1260, 672, 216, 36, 2
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OFFSET
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1,2
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COMMENTS
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REFERENCES
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A. D. Adeshola, V. Maltcev and A. Umar, Combinatorial results for certain semigroups of order-preserving full contraction mappings of a finite chain, (submitted).
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LINKS
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FORMULA
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T(n,1) = n and T(n,k) = 2(n-k+1)*C(n-1,k-1) if k > 1.
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EXAMPLE
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T (3,2) = 8 because there are exactly 8 order-preserving full contraction mappings (of a 3-chain) with exactly height 2, namely: (112), (122), (211), (221), (223), (233), (322), (332).
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CROSSREFS
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KEYWORD
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nonn
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AUTHOR
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STATUS
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approved
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