login

Year-end appeal: Please make a donation to the OEIS Foundation to support ongoing development and maintenance of the OEIS. We are now in our 61st year, we have over 378,000 sequences, and we’ve reached 11,000 citations (which often say “discovered thanks to the OEIS”).

A216212
Number of n step walks (each step +-1 starting from 0) which are never more than 4 or less than -4.
6
1, 2, 4, 8, 16, 30, 60, 110, 220, 400, 800, 1450, 2900, 5250, 10500, 19000, 38000, 68750, 137500, 248750, 497500, 900000, 1800000, 3256250, 6512500, 11781250, 23562500, 42625000, 85250000, 154218750, 308437500, 557968750, 1115937500, 2018750000, 4037500000
OFFSET
0,2
COMMENTS
The number of n step walks (each step +-1 starting from 0) which are never more than k or less than -k is given by a(n,k) = 2^n/(k+1)*Sum_{r=1..k+1} (-1)^r*cos((Pi*(2*r-1))/(2*(k+1)))^n*cot((Pi*(1-2*r))/(4*(k+1))), n<>0 if k even. Here we have k=4. - Herbert Kociemba, Sep 22 2020
FORMULA
a(n) = A068913(4,n).
G.f.: (1+2*x-x^2-2*x^3+x^4)/(1-5*x^2+5*x^4).
a(n) = 5*a(n-2) - 5*a(n-4), a(0) = 1, a(1) = 2, a(2) = 4, a(3) = 8, a(4) = 16.
a(2*n+1) = 2*A039717(n+1), a(2*n+2) = 4*A039717(n+1).
a(n) = (2^n/5)*Sum_{r=1..5} (-1)^r*cos(Pi*(2*r-1)/10)^n*cot(Pi*(1-2*r)/20), n>0. - Herbert Kociemba, Sep 22 2020
MATHEMATICA
nn=30; CoefficientList[Series[(1+x-x^2)^2/(1-5x^2+5x^4), {x, 0, nn}], x] (* Geoffrey Critzer, Jan 14 2014 *)
a[0, 4]=1; a[n_, k_]:=2^n/(k+1) Sum[(-1)^r Cos[(Pi (2r-1))/(2 (k+1))]^n Cot[(Pi (1-2r))/(4 (k+1))], {r, 1, k+1}]
Table[a[n, 4], {n, 0, 40}]//Round (* Herbert Kociemba, Sep 22 2020 *)
CROSSREFS
Cf. A068911, A068912, A068913, A178381 (starting from 4).
Sequence in context: A027423 A140410 A213368 * A164263 A283836 A244825
KEYWORD
nonn,walk
AUTHOR
Philippe Deléham, Mar 13 2013
STATUS
approved