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 A213777 Rectangular array:  (row n) = b**c, where b(h) = F(h), c(h) = F(h+1), F=A000045 (Fibonacci numbers), n>=1, h>=1, and ** = convolution. 3
 1, 3, 2, 7, 5, 3, 15, 12, 8, 5, 30, 25, 19, 13, 8, 58, 50, 40, 31, 21, 13, 109, 96, 80, 65, 50, 34, 21, 201, 180, 154, 130, 105, 81, 55, 34, 365, 331, 289, 250, 210, 170, 131, 89, 55, 655, 600, 532, 469, 404, 340, 275, 212, 144, 89, 1164, 1075, 965, 863 (list; table; graph; refs; listen; history; text; internal format)
 OFFSET 1,2 COMMENTS Principal diagonal:  A001870 Antidiagonal sums:  A152881 row 1,  (1,1,2,3,5,8,...)**(1,2,3,5,8,13,...): A023610(k-1) row 2,  (1,1,2,3,5,8,...)**(2,3,5,8,13,21,...): A067331(k-1) row 3,  (1,1,2,3,5,8,...)**(3,5,8,13,21,34,...) For a guide to related arrays, see A213500. LINKS Clark Kimberling, Antidiagonals n=1..80, flattened FORMULA T(n,k) = 2*T(n,k-1) + T(n,k-2) - 2*T(n,k-3) - T(n,k-4). G.f. for row n:  f(x)/g(x), where f(x) = F(n-1) + F(n-2)*x and g(x) = (1 - x - x^2)^2. T(n,k) = (k*Lucas(n+k+1) + Lucas(n)*Fibonacci(k))/5. - Ehren Metcalfe, Jul 10 2019 EXAMPLE Northwest corner (the array is read by falling antidiagonals): 1....3....7....15....30....58 2....5....12...25....50....96 3....8....19...40....80....154 5....13...31...65....130...250 8....21...50...105...210...404 13...34...81...170...340...654 MATHEMATICA b[n_] := Fibonacci[n]; c[n_] := Fibonacci[n + 1]; t[n_, k_] := Sum[b[k - i] c[n + i], {i, 0, k - 1}] TableForm[Table[t[n, k], {n, 1, 10}, {k, 1, 10}]] Flatten[Table[t[n - k + 1, k], {n, 12}, {k, n, 1, -1}]] r[n_] := Table[t[n, k], {k, 1, 60}]  (* A213777 *) Table[t[n, n], {n, 1, 40}] (* A001870 *) s[n_] := Sum[t[i, n + 1 - i], {i, 1, n}] Table[s[n], {n, 1, 50}] (* A152881 *) CROSSREFS Cf. A213500. Sequence in context: A128140 A213579 A137225 * A118834 A255547 A087468 Adjacent sequences:  A213774 A213775 A213776 * A213778 A213779 A213780 KEYWORD nonn,tabl,easy AUTHOR Clark Kimberling, Jun 21 2012 STATUS approved

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Last modified January 26 13:09 EST 2022. Contains 350598 sequences. (Running on oeis4.)