OFFSET
1,5
COMMENTS
Let row n+1 be (c0, c1, c2,...,cn). Then
c0*x^n + c1*x^(n-1) +...+ cn=(x+b0)(x+b1)...(x+bm),
where (b0,b1,b2,...,bm) is row n.
FORMULA
row n+1: f(0,r), f(1,r),...f(n,r), where f(k,r)=(k-th elementary symmetric function), r=(row n).
EXAMPLE
First five rows:
1
1...1
1...2....1
1...4....5....2
1...12...49...78...40
The factorization property is illustrated by
x^2 + 2x + 1 -> (x+1)(x+2)(x+1) = x^3 + 4x^2 + 5x + 2.
MATHEMATICA
s =.; s[1] = {1};
Prepend[Table[s[z] = Table[SymmetricPolynomial
[k, s[z - 1]], {k, 0, z - 1}], {z, 2, 7}], s[1]]
% // TableForm (* A203300 triangle *)
%% // Flatten (* A203300 sequence *)
(* Peter J. C. Moses, Dec 30 2011 *)
CROSSREFS
KEYWORD
nonn,tabl
AUTHOR
Clark Kimberling, Dec 31 2011
STATUS
approved