OFFSET
1,1
COMMENTS
Column 1 of A202447.
LINKS
R. H. Hardin, Table of n, a(n) for n = 1..210
FORMULA
Empirical: a(n) = (2/3)*n^3 + 8*n^2 + (100/3)*n + 34 for n>1.
Conjectures from Colin Barker, May 28 2018: (Start)
G.f.: 2*x*(40 - 91*x + 76*x^2 - 25*x^3 + 2*x^4) / (1 - x)^4.
a(n) = 4*a(n-1) - 6*a(n-2) + 4*a(n-3) - a(n-4) for n>5.
(End)
EXAMPLE
Some solutions for n=4:
1 0 1 1 1 1 1 0 0 1 0 1 0 0 0 1 0 0 0 0 0
0 1 0 1 0 1 0 0 0 0 1 0 1 0 1 0 1 1 0 1 1
1 1 1 1 0 1 1 0 0 1 0 1 1 0 0 1 1 1 0 0 0
0 1 0 1 0 1 0 0 0 0 0 0 1 0 1 0 1 1 0 1 0
0 1 1 1 0 1 1 0 0 1 0 1 1 0 0 1 1 1 0 1 0
0 1 0 1 0 1 1 0 0 0 0 0 1 0 0 1 1 1 0 1 0
CROSSREFS
KEYWORD
nonn
AUTHOR
R. H. Hardin, Dec 19 2011
STATUS
approved