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A194560
G.f.: Sum_{n>=1} G_n(x)^n where G_n(x) = x + x*G_n(x)^n.
9
1, 2, 2, 4, 2, 10, 2, 20, 14, 49, 2, 217, 2, 438, 310, 1580, 2, 6352, 2, 18062, 7824, 58799, 2, 258971, 2532, 742915, 246794, 2729095, 2, 11154954, 2, 35779660, 8414818, 129644809, 242354, 531132915, 2, 1767263211, 300830821, 6593815523, 2, 26289925026, 2, 91708135773
OFFSET
1,2
COMMENTS
Number of Dyck n-paths with all ascents of equal length. - David Scambler, Nov 17 2011
From Gus Wiseman, Feb 15 2019: (Start)
Also the number of uniform (all blocks have the same size) non-crossing set partitions of {1,...,n}. For example, the a(3) = 2 through a(6) = 10 uniform non-crossing set partitions are:
{{123}} {{1234}} {{12345}} {{123456}}
{{1}{2}{3}} {{12}{34}} {{1}{2}{3}{4}{5}} {{123}{456}}
{{14}{23}} {{126}{345}}
{{1}{2}{3}{4}} {{156}{234}}
{{12}{34}{56}}
{{12}{36}{45}}
{{14}{23}{56}}
{{16}{23}{45}}
{{16}{25}{34}}
{{1}{2}{3}{4}{5}{6}}
(End)
LINKS
Eric Weisstein's World of Mathematics, Dyck Path.
FORMULA
a(n) = Sum_{d|n} C(n,d)/(n-d+1).
G.f.: Sum_{n>=1} Series_Reversion( x/(1+x^n) )^n.
EXAMPLE
G.f.: A(x) = x + 2*x^2 + 2*x^3 + 4*x^4 + 2*x^5 + 10*x^6 + 2*x^7 + ...
where
A(x) = G_1(x) + G_2(x)^2 + G_3(x)^3 + G_4(x)^4 + G_5(x)^5 + ...
and G_n(x) = x + x*G_n(x)^n is given by:
G_n(x) = Sum_{k>=0} C(n*k+1,k)/(n*k+1)*x^(n*k+1),
G_n(x)^n = Sum_{k>=1} C(n*k,k)/(n*k-k+1)*x^(n*k);
the first few expansions of G_n(x)^n begin:
G_1(x) = x + x^2 + x^3 + x^4 + x^5 + ...
G_2(x)^2 = x^2 + 2*x^4 + 5*x^6 + 14*x^8 + ... + A000108(n)*x^(2*n) + ...
G_3(x)^3 = x^3 + 3*x^6 + 12*x^9 + 55*x^12 + ... + A001764(n)*x^(3*n) + ...
G_4(x)^4 = x^4 + 4*x^8 + 22*x^12 + 140*x^16 + ... + A002293(n)*x^(4*n) + ...
G_5(x)^5 = x^5 + 5*x^10 + 35*x^15 + 285*x^20 + ... + A002294(n)*x^(5*n) + ...
MATHEMATICA
Table[Sum[Binomial[n, d]/(n-d+1), {d, Divisors[n]}], {n, 20}] (* Gus Wiseman, Feb 15 2019 *)
PROG
(PARI) {a(n)=if(n<1, 0, sumdiv(n, d, binomial(n, d)/(n-d+1)))}
(PARI) {a(n)=polcoeff(sum(m=1, n, serreverse(x/(1+x^m+x*O(x^n)))^m), n)}
KEYWORD
nonn
AUTHOR
Paul D. Hanna, Aug 28 2011
STATUS
approved