A189028 Zero-one sequence based on the sequence (5n-4): a(A016861(k))=a(k); a(A047203(k))=1-a(k); a(1)=0.

0, 1, 0, 1, 0, 1, 1, 0, 0, 1, 0, 1, 0, 1, 0, 1, 1, 0, 1, 0, 0, 0, 1, 0, 1, 1, 1, 1, 0, 1, 1, 0, 0, 0, 0, 0, 1, 0, 0, 1, 0, 1, 1, 1, 1, 1, 0, 1, 1, 0, 0, 1, 0, 0, 0, 1, 0, 0, 1, 0, 0, 0, 1, 1, 0, 1, 1, 1, 1, 0, 0, 1, 1, 0, 1, 1, 1, 1, 0, 0, 1, 1, 0, 0, 0, 0, 0, 1, 1, 0, 1, 0, 1, 0, 0, 0, 0, 0, 1, 1, 0, 0, 0, 1, 1, 0, 1, 1, 1, 0, 1, 0, 1, 0, 1, 0, 0, 1, 1, 1, 1, 1, 1, 0, 0, 1, 1, 1

Offset

1

Links

Table of n, a(n) for n=1..128.

Example

Let u=A016861 and v=A047203, so that u(n)=5n-4 and v=complement(u) for n>=1.  Then a is a self-generating zero-one sequence with initial value a(1)=0 and a(u(k))=a(k); a(v(k))=1-a(k).

Mathematica

u[n_] := 5n-4;  (*A016861*)
a[1] = 0; h = 128;
c = (u[#1] &) /@ Range[h];
d = (Complement[Range[Max[#1]], #1] &)[c]; (*A047203*)
Table[a[d[[n]]] = 1 - a[n], {n, 1, h - 1}];
Table[a[c[[n]]] = a[n], {n, 1, h}]   (*A189028*)
Flatten[Position[%, 0]]  (*A189029*)
Flatten[Position[%%, 1]] (*A189030*)

Crossrefs

Cf. A188967, A189029, A189030.

Sequence in context: A353681 A285515 A190204 * A301850 A189031 A189212

Adjacent sequences: A189025 A189026 A189027 * A189029 A189030 A189031

Keyword

nonn

Author

Clark Kimberling, Apr 15 2011

Status

approved