|
|
A182995
|
|
Sum of parts of the n-th subsection of the head of the last section of the set of partitions of any odd integer >= 2n+1.
|
|
7
|
|
|
3, 7, 18, 44, 82, 158, 303, 507, 873, 1470, 2354, 3756, 5923, 9065, 13815, 20824, 30853, 45365, 66210, 95415, 136696, 194414, 274057, 384136, 535219, 740559, 1019529, 1396212, 1901533, 2577918, 3479291, 4673711, 6253003, 8332767
(list;
graph;
refs;
listen;
history;
text;
internal format)
|
|
|
OFFSET
|
1,1
|
|
COMMENTS
|
The last section of the set of partitions of 2n+1 contains n subsections.
Also first differences of A182737. - Omar E. Pol, Mar 03 2011
|
|
LINKS
|
|
|
FORMULA
|
|
|
EXAMPLE
|
a(5)=82 because the 5th subsection of the head of the last section of any odd integer >= 11 looks like this:
(11 . . . . . . . . . . )
( 6 . . . . . 5 . . . . )
( 7 . . . . . . 4 . . . )
( 8 . . . . . . . 3 . . )
( 4 . . . 4 . . . 3 . . )
( 5 . . . . 3 . . 3 . . )
. (2 . )
. (2 . )
. (2 . )
. (2 . )
. (2 . )
. (2 . )
. (2 . )
. (2 . )
There are 21 parts whose sum is 11+6+5+7+4+8+3+4+4+3+5+3+3+2+2+2+2+2+2+2+2 = 11*6 + 2*8 = 82, so a(5) = 82.
|
|
CROSSREFS
|
|
|
KEYWORD
|
nonn
|
|
AUTHOR
|
|
|
EXTENSIONS
|
a(17) corrected and more terms from Omar E. Pol, Mar 03 2011.
|
|
STATUS
|
approved
|
|
|
|