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A180360
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Table t(n,k) is the number of ways to partition 1 into k fractions using the Farey fractions of order n, read row by row.
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3
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1, 1, 1, 1, 2, 1, 1, 3, 2, 1, 1, 5, 4, 2, 1, 1, 6, 6, 5, 3, 1, 1, 9, 10, 8, 5, 2, 1, 1, 11, 14, 13, 10, 6, 3, 1, 1, 14, 20, 22, 21, 15, 9, 4, 1, 1, 16, 26, 36, 39, 33, 22, 11, 4, 1, 1, 21, 36, 47, 49, 40, 27, 14, 6, 2, 1, 1, 23, 44, 70, 87, 89, 76, 53, 31, 14, 5, 1, 1, 29, 58, 88, 105, 103, 87
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OFFSET
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1,5
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COMMENTS
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...
..1
..1...1
..1...2...1
..1...3...2...1
..1...5...4...2...1
..1...6...6...5...3...1
..1...9..10...8...5...2...1
..1..11..14..13..10...6...3...1
..1..14..20..22..21..15...9...4...1
..1..16..26..36..39..33..22..11...4...1
..1..21..36..47..49..40..27..14...6...2...1
..1..23..44..70..87..89..76..53..31..14...5...1
..1..29..58..88.105.103..87..60..36..17...7...2...1
...
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LINKS
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EXAMPLE
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t(6,3) = 6 because 1 = 2/3+1/6+1/6 = 3/5+1/5+1/5 = 1/2+1/3+1/6 = 1/2+1/4+1/4 = 2/5+2/5+1/5 = 1/3+1/3+1/3.
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MATHEMATICA
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Farey[n_] := Union@ Flatten@ Table[a/b, {b, n}, {a, b}]; t[n_, k_] := Length@ IntegerPartitions[1, {k}, Farey@ n]; Table[ t[n, k], {n, 13}, {k, n}] // Flatten
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CROSSREFS
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KEYWORD
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AUTHOR
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STATUS
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approved
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