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A178189
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Numerators of sum (1/5)^((k^2+3k)/2) from k=1 to n.
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1
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OFFSET
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1,2
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COMMENTS
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Series of the kind m^((k^2+3k)/2) from k=1 to n was studied by Bernoulli and Euler.
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LINKS
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MATHEMATICA
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aa = {}; m = 1/5; sum = 0; Do[sum = sum + m^((n + 3) n/2); AppendTo[aa, Numerator[sum]], {n, 1, 20}]; aa (*Artur Jasinski*)
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PROG
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(PARI) a(n) = numerator(sum(k=1, n, (1/5)^((k^2+3*k)/2))); \\ Michel Marcus, Sep 09 2013
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CROSSREFS
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KEYWORD
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nonn,frac
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AUTHOR
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STATUS
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approved
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