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A178186
Sum 3^((k^2+3k)/2) from k=1 to n.
1
9, 252, 19935, 4802904, 3491587305, 7629089072292, 50039174188071999, 984820941357799304880, 58150721823981417489695049, 10301109611599361435391036962892, 5474411390529830981438591324606714655
OFFSET
1,1
COMMENTS
Series of the kind m^((k^2+3k)/2) from k=1 to n was studied by Bernoulli and Euler.
LINKS
MATHEMATICA
aa = {}; m = 3; sum = 0; Do[sum = sum + m^((n + 3) n/2); AppendTo[aa, sum], {n, 1, 20}]; aa (*Artur Jasinski*)
Table[Sum[3^((k^2+3k)/2), {k, n}], {n, 20}] (* Harvey P. Dale, Jul 10 2020 *)
Accumulate[Table[3^((k^2+3k)/2), {k, 15}]] (* Harvey P. Dale, Mar 25 2023 *)
PROG
(PARI) a(n) = sum(k=1, n, 3^((k^2+3*k)/2)); \\ Michel Marcus, Sep 09 2013
CROSSREFS
KEYWORD
nonn
AUTHOR
Artur Jasinski, May 21 2010
STATUS
approved