

A175901


Numbers n such that there exists a smaller number k such that k^21 has exactly the same set of distinct prime divisors as n^21


4



7, 17, 19, 26, 31, 41, 49, 53, 55, 65, 71, 76, 97, 109, 127, 129, 161, 191, 197, 199, 209, 239, 241, 251, 271, 289, 295, 351, 391, 401, 433, 449, 485, 511, 575, 577, 626, 647, 649, 685, 701, 703, 721, 727, 799, 811, 881, 883, 901, 967, 989, 1025, 1055, 1079
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OFFSET

1,1


LINKS

Table of n, a(n) for n=1..54.


FORMULA

a(1)=7 because set of prime divisors of 7^21 is the same as for 5^21. The set is {2,3}.


MATHEMATICA

aa = {}; bb = {}; Do[k = n^2  1; c = FactorInteger[k]; b = {}; Do[AppendTo[b, c[[m]][[1]]], {m, 1, Length[c]}]; If[Position[aa, b] != {}, AppendTo[bb, n], AppendTo[aa, b]], {n, 2, 10000}]; bb (*Artur Jasinski*)


PROG

(PARI) isok(n) = {pfs = factor(n^21)[, 1]; for (k = 2, n1, if (factor(k^21)[, 1] == pfs, return (1)); ); return (0); } \\ Michel Marcus, Nov 04 2013


CROSSREFS

Cf. A175902 (for corresponding k).
Sequence in context: A071845 A084704 A198032 * A140566 A278785 A156005
Adjacent sequences: A175898 A175899 A175900 * A175902 A175903 A175904


KEYWORD

nonn


AUTHOR

Artur Jasinski, Oct 11 2010


EXTENSIONS

Edited by N. J. A. Sloane, Oct 14 2010


STATUS

approved



