OFFSET
1,1
COMMENTS
a(1) = 2, a(n) = A006512(n-1) for 2 <= n <= 82, a(83) = 2999. Sequence is the union of A006512 and A175080. Subsequence of A175072. Primes q with some results of {2, 28, 36, 52, 58, 66, ... } under first step of iteration of {r mod (max prime p < r)} starting at r = q, i.e. number 2 and primes q such that difference q and previous prime is equal to some of the values 2, 28, 36, 52, 58, 66, ...
Not the same as A094743: contains 2999, 3299, 5147, 5981, 8999, 9587, 10037, 10427, 10559, 10937, 11579, 12889, ... that are absent from that sequence. Up to 10^9, there are 3247366 terms in this sequence that are not in A094743, though every term from that sequence appears here. Is A094743 a subsequence of this sequence? - Charles R Greathouse IV, Jan 12 2022
It suffices to stop after the iterations yield a number less than 5 and check if the result is 2. Under this procedure, 2 takes 0 iterations, 5 is the first prime to take 1 iteration, 29 is the first to take 2 iterations, 2999 is the first to take 3 iterations, and 401429925999155063 is the first to take 4 iterations. - Charles R Greathouse IV, Jan 14 2022
LINKS
Charles R Greathouse IV, Table of n, a(n) for n = 1..10000
FORMULA
EXAMPLE
Iteration procedure for a(5) = 19: 19 mod 17 = 2. Iteration procedure for a(83) = 2999: 2999 mod 2971 = 28, 28 mod 23 = 5, 5 mod 3 = 2.
MATHEMATICA
fQ[p_] := Block[{r = p}, While[r > 2, r = Mod[r, NextPrime[r, -1]]]; r == 2]; Select[ Prime@ Range@ 253, fQ] (* Robert G. Wilson v, Aug 09 2010 *)
PROG
(PARI) is(n)=if(!isprime(n), return(0)); while(n>4, n-=precprime(n-1)); n==2 \\ Charles R Greathouse IV, Jan 12 2022
(PARI) has(n)=while(n>4, n-=precprime(n-1)); n==2
list(lim)=my(v=List([2]), p=3); forprime(q=5, lim, if(has(q-p), listput(v, q)); p=q); Vec(v) \\ Charles R Greathouse IV, Jan 12 2022
CROSSREFS
KEYWORD
nonn
AUTHOR
Jaroslav Krizek, Jan 23 2010
EXTENSIONS
More terms from Robert G. Wilson v, Aug 09 2010
A175080 inserted in comment - R. J. Mathar, Sep 25 2010
STATUS
approved
