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A175003
Triangle read by rows demonstrating Euler's pentagonal theorem for partition numbers.
26
1, 1, 1, 2, 1, 3, 2, 5, 3, -1, 7, 5, -1, 11, 7, -2, -1, 15, 11, -3, -1, 22, 15, -5, -2, 30, 22, -7, -3, 42, 30, -11, -5, 56, 42, -15, -7, 1, 77, 56, -22, -11, 1, 101, 77, -30, -15, 2, 135, 101, -42, -22, 3, 1, 176, 135, -56, -30, 5, 1, 231, 176, -77, -42, 7, 2
OFFSET
1,4
COMMENTS
Row sums = A000041 starting with offset 1.
Sum of n-th row terms = leftmost term of next row, such that terms in each row demonstrate Euler's pentagonal theorem.
Let Q = triangle A027293 with partition numbers in each column.
Let M = a diagonalized variant of A080995 as the characteristic function of the generalized pentagonal numbers starting with offset 1: (1, 1, 0, 0, 1,...)
Sign the 1's: (++--++...) getting (1, 1, 0, 0, -1, 0, -1,...) which is the diagonal of matrix M, (as an infinite lower triangular matrix with the rest zeros).
Triangle A175003 = Q*M, with deleted zeros.
Column k starts at row A001318(k). - Omar E. Pol, Sep 21 2011
From Omar E. Pol, Apr 22 2014: (Start)
Row n has length A235963(n).
For Euler's pentagonal theorem for the sum of divisors see A238442.
Note that both of Euler's pentagonal theorems refer to generalized pentagonal numbers (A001318), not to pentagonal numbers (A000326). (End)
FORMULA
T(n,k) = A057077(k-1)*A000041(A195310(n,k)), n >= 1, k >= 1. - Omar E. Pol, Sep 21 2011
EXAMPLE
Triangle begins:
1;
1, 1;
2, 1;
3, 2;
5, 3, -1;
7, 5, -1;
11, 7, -2, -1;
15, 11, -3, -1;
22, 15, -5, -2;
30, 22, -7, -3;
42, 30, -11, -5;
56, 42, -15, -7, 1;
77, 56, -22, -11, 1;
101, 77, -30, -15, 2;
...
CROSSREFS
KEYWORD
tabf,sign
AUTHOR
Gary W. Adamson, Apr 03 2010
EXTENSIONS
Corrected and extended by Omar E. Pol, Feb 14 2013
STATUS
approved