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A235963
n appears (n+1)/(1 + (n mod 2)) times.
6
0, 1, 2, 2, 2, 3, 3, 4, 4, 4, 4, 4, 5, 5, 5, 6, 6, 6, 6, 6, 6, 6, 7, 7, 7, 7, 8, 8, 8, 8, 8, 8, 8, 8, 8, 9, 9, 9, 9, 9, 10, 10, 10, 10, 10, 10, 10, 10, 10, 10, 10, 11, 11, 11, 11, 11, 11, 12, 12, 12, 12, 12, 12, 12, 12, 12, 12, 12, 12, 12, 13, 13, 13, 13, 13, 13, 13
OFFSET
0,3
COMMENTS
n appears A001318(n+1) - A001318(n) = A026741(n+1) times.
Sum_{k=0...a(n)} (-1)^ceiling(k/2)*p(n-G(k)) = 0 for n>0, where p(n)=A000041(n) is the partition function, and G(k)=A001318(k) denotes the generalized pentagonal numbers.
Row lengths of A238442, n >= 1. - Omar E. Pol, Dec 22 2016
LINKS
FORMULA
Let t = (sqrt(n*8/3 + 1) - 1)/2 + 1/3 and let k = floor(t); then a(n) = 2k if t - k < 2/3, 2k+1 otherwise. - Jon E. Schoenfield, Jun 13 2017
a(n) = m if n+1>A001318(m) and a(n) = m-1 otherwise where m = floor(sqrt(8(n+1)/3)). - Chai Wah Wu, Nov 23 2024
EXAMPLE
As triangle:
0;
1;
2, 2, 2;
3, 3;
4, 4, 4, 4, 4;
5, 5, 5;
6, 6, 6, 6, 6, 6, 6;
7, 7, 7, 7;
8, 8, 8, 8, 8, 8, 8, 8, 8;
...
MAPLE
T:= n-> n$(n+1)/(n mod 2+1):
seq(T(n), n=0..13); # Alois P. Heinz, Nov 23 2024
MATHEMATICA
Table[Table[n, {(n + 1)/(1 + Mod[n, 2])}], {n, 0, 14}]//Flatten (* T. D. Noe, Jan 29 2014 *)
PROG
(Python)
from math import isqrt
def A235963(n): return (m:=isqrt((n+1<<3)//3))-(n+1<=(m*(3*m+4)+1 if m&1 else m*(3*m+2))>>3) # Chai Wah Wu, Nov 23 2024
CROSSREFS
KEYWORD
nonn,tabf
AUTHOR
Mircea Merca, Jan 17 2014
STATUS
approved