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A174057 Semi-sums (means) of a Fermat prime and a Mersenne prime. 3
3, 4, 5, 6, 10, 12, 17, 18, 24, 65, 66, 72, 130, 132, 144, 192, 4097, 4098, 4104, 4224, 32770, 32772, 32784, 32832, 36864, 65537, 65538, 65544, 65664, 98304, 262145, 262146, 262152, 262272, 294912, 1073741825, 1073741826, 1073741832 (list; graph; refs; listen; history; text; internal format)
OFFSET
1,1
COMMENTS
The subsequence of prime semi-sums (means) of a Fermat prime and a Mersenne prime begins: 3, 5, 17, 65537 = (3 + 131071)/2. R. J. Mathar, on the remaining primes in the half sum, searched through all sums that can be created from the existing values of the two OEIS sequences, and that the next Fermat prime is known to be > 2^(2^32) + 1. So it is safe to say that the next prime > 65537 in the half sum (if it exists) is larger than 85070591730234615865843651857942085632, because adding that huge next Fermat prime would lead to even larger numbers. Of course one could easily boost that estimate by using the b-file of A000668.
LINKS
FORMULA
{(A019434(i) + A000668(j))/2}. {(((2^p)-1) + (2^(2^k)+1))/2 = 2^(p-1) + 2^((2^k)-1) for p in A000043 and k in {0,1,2,3,4}}.
EXAMPLE
a(1) = 3 = half of first Mersenne prime + first Fermat prime = (3+3)/2.
a(2) = 4 = half of first Mersenne prime + 2nd Fermat prime = (3+5)/2.
a(3) = 5 = half of 2nd Mersenne prime + first Fermat prime = (7+3)/2.
a(4) = 6 = half of 2nd Mersenne prime + 2nd Fermat prime = (7+5)/2.
a(5) = 10 = half of 2nd Mersenne prime + 3rd Fermat prime = (3+17)/2.
CROSSREFS
Cf. A000668, A171251-A171255, A155877 Sums of three Fermat numbers, A166484 Prime sums of three Fermat numbers, A174055, A174056.
Sequence in context: A263118 A219041 A218946 * A335231 A164977 A103033
KEYWORD
nonn
AUTHOR
Jonathan Vos Post, Mar 06 2010
STATUS
approved

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Last modified April 19 11:14 EDT 2024. Contains 371791 sequences. (Running on oeis4.)