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A166464 a(n) = (3+2n+6n^2+4n^3)/3. 10
1, 5, 21, 57, 121, 221, 365, 561, 817, 1141, 1541, 2025, 2601, 3277, 4061, 4961, 5985, 7141, 8437, 9881, 11481, 13245, 15181, 17297, 19601, 22101, 24805, 27721, 30857, 34221, 37821, 41665, 45761, 50117, 54741, 59641 (list; graph; refs; listen; history; text; internal format)
OFFSET
0,2
COMMENTS
Atomic number of first transition metal of period 2n (n>3) or of the element after n-th alkaline earth metal. This can be calculated by finding the sum of the first n even squares plus 1. - Natan Arie Consigli, Jul 03 2016
REFERENCES
JANET,Charles, La structure du Noyau de l'atome,consideree dans la Classification periodique,des elements chimiques,1927 (Novembre),N. 2,BEAUVAIS,67 pages,3 leaflets.
LINKS
FORMULA
a(n) = a(n-1)+4+8n+4n^2 or a(n)-a(n-1)=4*(n+1)^2 = A016742(n+1).
a(n) = 2a(n-1)-a(n-2)-4+8n or a(n)-2a(n-1)+a(n-2)=-4+8n = A017113(n+1).
a(n) = 3a(n-1)-3a(n-2)+a(n-3)+8 or a(n)-3a(n-1)+3a(n-2)-a(n-3)=8 =A010731.
a(n) = 4a(n-1)-6a(n-2)+4a(n-3)-a(n-4) or a(n)-4a(n-1)+6a(n-2)-4a(n-3)+a(n-4)=0 = A000004(n).
Binomial transform of quasi-finite sequence 1,4,12,8,0,(0 continued).
G.f.: (1+x+7*x^2-x^3)/(1-x)^4. - R. J. Mathar, Feb 15 2010
a(n) = A018227(2n) + 3; a(n) = A002492(n) + 1. - Natan Arie Consigli, Jul 03 2016
MATHEMATICA
Table[(3 + 2*n + 6*n^2 + 4*n^3)/3, {n, 0, 100}](* G. C. Greubel, May 15 2016 *)
PROG
(PARI) a(n)=(3+2*n+6*n^2+4*n^3)/3 \\ Charles R Greathouse IV, Oct 07 2015
CROSSREFS
Sequence in context: A146854 A299120 A033275 * A059859 A146617 A245240
KEYWORD
nonn,easy
AUTHOR
Paul Curtz, Oct 14 2009
EXTENSIONS
Edited by N. J. A. Sloane, Oct 17 2009
More terms a(11)-a(35) from Vincenzo Librandi, Oct 17 2009
STATUS
approved

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Last modified April 25 01:35 EDT 2024. Contains 371964 sequences. (Running on oeis4.)