OFFSET
1,1
COMMENTS
For every n>=1, A104272(n) >= A080359(n), and the sequence shows where the inequality becomes an equality.
Let prime(m) < a(n)/2 < prime(m+1); then there exist primes p<q such that p is in the interval (2*Prime(m), a(n)) and q is in the interval (a(n), 2*Prime(m+1)).
For example, a(2) = 71, 31 < a(2)/2 < 37 and intervals (62,71), (71,74) contain the primes p = 67 and q = 73 respectively.
Let us call a prime p compatible with another prime q, if the intervals (p/2,q/2) and (p,q], if q>p, (or intervals (q/2,p/2) and (q,p], if q<p) contain the same number of primes. If p is compatible with no other prime, we call it a peculiar prime. The sequence lists the peculiar primes. [Vladimir Shevelev, Apr 25 2012]
LINKS
V. Shevelev, On critical small intervals containing primes, arXiv:0908.2319 [math.NT] [From Vladimir Shevelev, Aug 20 2009]
V. Shevelev, Ramanujan and Labos primes, their generalizations, and classifications of primes, J. Integer Seq. 15 (2012) Article 12.5.4
J. Sondow, J. W. Nicholson, and T. D. Noe, Ramanujan Primes: Bounds, Runs, Twins, and Gaps, J. Integer Seq. 14 (2011) Article 11.6.2
FORMULA
EXAMPLE
a(2)=71, such that 31<71/2<37, and we see that p=67 is in interval (62, 71) and q=73 is in interval (71, 74).
MATHEMATICA
CROSSREFS
KEYWORD
nonn
AUTHOR
Vladimir Shevelev, Aug 15 2009
EXTENSIONS
Terms beyond 659 from R. J. Mathar, Dec 17 2009
STATUS
approved