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A162864
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Integers n, divisible by six, for which t = (4^n - 5 * 2^n - 4 * 4^(n^2 - 2n) + 8 * 2^(n^2 - 2n)) / (4 * (n^3 - n)) is an integer
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0
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6, 12, 18, 30, 36, 42, 60, 72, 108, 180, 192, 240, 270, 312, 420, 432, 462, 600, 660, 810, 882, 1092, 1152, 1290, 1296, 1302, 1320, 1620, 1722, 1872, 2028, 2112, 2268, 2310, 2340, 2592, 2688, 2700, 2790, 2970, 3000, 3120, 3258, 3300, 3360, 3390, 3528, 3540
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OFFSET
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1,1
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COMMENTS
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Then n - 1 and n + 1 are almost always a pair of twin primes, and the set of these should be an infinite subset of all twin primes.
If n - 1 and n + 1 are simultaneously composite, this occurs very rarely.
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LINKS
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CROSSREFS
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KEYWORD
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easy,nonn
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AUTHOR
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STATUS
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approved
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