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A158817
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a(n) = (binomial(2^n, 2^(n-1)) - binomial(2^(n-1), 2^(n-2)))/2^n.
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1
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OFFSET
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2,2
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LINKS
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Gyula O. H. Katona and Leonid Makar-Limanov, A problem for abelian groups, Asian-Eur. J. Math. 1 (2008), no. 2, 237--241. (Reviewer: Thomas Britz) 20K01 (05B40 94B65).
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FORMULA
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a(n) = ( binomial(2^n, 2^(n-1)) - binomial(2^(n-1), 2^(n-2)) )/2^n.
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MATHEMATICA
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Table[(Binomial[2^n, 2^(n-1)] -Binomial[2^(n-1), 2^(n-2)])/2^n, {n, 2, 12}]
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PROG
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(Sage) [( binomial(2^n, 2^(n-1)) - binomial(2^(n-1), 2^(n-2)) )/2^n for n in (2..12)] # G. C. Greubel, Dec 22 2021
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CROSSREFS
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KEYWORD
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nonn
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AUTHOR
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STATUS
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approved
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