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A155495
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Triangle read by rows: t(n,m) = binomial(2*n,2*m) * binomial(n,m).
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5
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1, 1, 1, 1, 12, 1, 1, 45, 45, 1, 1, 112, 420, 112, 1, 1, 225, 2100, 2100, 225, 1, 1, 396, 7425, 18480, 7425, 396, 1, 1, 637, 21021, 105105, 105105, 21021, 637, 1, 1, 960, 50960, 448448, 900900, 448448, 50960, 960, 1, 1, 1377, 110160, 1559376, 5513508, 5513508, 1559376, 110160, 1377, 1
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OFFSET
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0,5
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COMMENTS
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T(n,k) equals (-1)^k times the coefficient of x^k in 3F2(-n,-n,-n+1/2;1,1/2;x); see Mathematica code below. - John M. Campbell, Oct 23 2011
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LINKS
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FORMULA
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T(n, k) = binomial(n, k)*binomial(2*n, 2*k).
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EXAMPLE
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Table starts:
1;
1, 1;
1, 12, 1;
1, 45, 45, 1;
1, 112, 420, 112, 1;
1, 225, 2100, 2100, 225, 1;
1, 396, 7425, 18480, 7425, 396, 1;
1, 637, 21021, 105105, 105105, 21021, 637, 1;
1, 960, 50960, 448448, 900900, 448448, 50960, 960, 1;
1, 1377, 110160, 1559376, 5513508, 5513508, 1559376, 110160, 1377, 1;
1, 1900, 218025, 4651200, 26453700, 46558512, 26453700, 4651200, 218025, 1900, 1;
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MAPLE
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seq(seq(binomial(2*n, 2*m)*binomial(n, m), m=0..n), n=0..10); # Robert Israel, Jun 12 2017
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MATHEMATICA
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T[n_, k_]:= Binomial[2*n, 2*k]*Binomial[n, k]; Table[T[n, k], {n, 0, 12}, {k, 0, n}]//Flatten
Abs[Flatten[Table[CoefficientList[HypergeometricPFQ[{-n, -n, -n+1/2}, {1, 1/2}, x], x], {n, 1, 20}]]] (* or *)
T[n_, k_]:= (-1)^k*Coefficient[HypergeometricPFQ[{-n, -n, -n+1/2}, {1, 1/2}, x], x^k] (* John M. Campbell, Oct 23 2011 *)
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PROG
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(Magma) [Binomial(n, k)*Binomial(2*n, 2*k): k in [0..n], n in [0..12]]; // G. C. Greubel, May 29 2021
(Sage) flatten([[binomial(n, k)*binomial(2*n, 2*k) for k in (0..n)] for n in (0..12)]) # G. C. Greubel, May 29 2021
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CROSSREFS
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KEYWORD
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AUTHOR
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STATUS
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approved
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