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A153063
a(n)=floor(b(n)), where b(0)=1, b(n)=b(n-1)^2-n^b(n-1).
1
1, 0, -1, 0, -3, 4, -2092, 4372582
OFFSET
0,5
COMMENTS
The supplied Mathematica and PARI code corresponds to an initial value a(-1)=b(-1)=1 from which a(0)=b(0) is computed to be equal to 1.
The next term is approximately
-1.642155991293887705947531213655414816023738489781202992764677529*10^3948835
and is too large to display here. - Robert G. Wilson v, Nov 27 2010
MATHEMATICA
a=1; lst={}; Do[a=a^2-n^a; AppendTo[lst, Floor[a]], {n, 0, 7}]; lst
PROG
(PARI) a=1; for(n=0, 7, print1(floor(a=a^2-n^a)", ")) \\ - R. Gerbicz, Nov 27 2010
KEYWORD
sign
AUTHOR
EXTENSIONS
Definition clarified by R. J. Mathar, R. Gerbicz and M. F. Hasler, Nov 27 2010
STATUS
approved