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A153064
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a(n) = floor(b(n)) where b(-1)=2, b(n)=b(n-1)^2-n^b(n-1).
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0
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OFFSET
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-1,1
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COMMENTS
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a(4) ~ -5.3069609889*10^637609736, and is too large for display. - D. S. McNeil, Nov 28 2010
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LINKS
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MATHEMATICA
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a=2; lst={}; Do[a=a^2-n^a; AppendTo[lst, Floor[a]], {n, 0, 3}]; lst
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PROG
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(PARI) print1(a=2); for(n=0, 3, print1(", "floor(a=a^2-n^a)))
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CROSSREFS
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KEYWORD
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sign
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AUTHOR
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EXTENSIONS
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STATUS
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approved
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