|
|
A152949
|
|
a(n) = 3 + binomial(n-1,2).
|
|
3
|
|
|
3, 3, 4, 6, 9, 13, 18, 24, 31, 39, 48, 58, 69, 81, 94, 108, 123, 139, 156, 174, 193, 213, 234, 256, 279, 303, 328, 354, 381, 409, 438, 468, 499, 531, 564, 598, 633, 669, 706, 744, 783, 823, 864, 906, 949, 993, 1038, 1084, 1131, 1179, 1228, 1278, 1329, 1381
(list;
graph;
refs;
listen;
history;
text;
internal format)
|
|
|
OFFSET
|
1,1
|
|
COMMENTS
|
a(1)=3; then add 0 to the first number, then 1,2,3,4,... and so on.
|
|
LINKS
|
|
|
FORMULA
|
Sum_{n>=1} 1/a(n) = 1/3 + 2*Pi*tanh(sqrt(23)*Pi/2)/sqrt(23). - Amiram Eldar, Dec 13 2022
|
|
MAPLE
|
seq(coeff(series(x*(4*x^2-6*x+3)/(1-x)^3, x, n+1), x, n), n = 1 .. 55); # Muniru A Asiru, Oct 28 2018
|
|
MATHEMATICA
|
s=3; lst={3}; Do[s+=n; AppendTo[lst, s], {n, 0, 5!}]; lst
|
|
PROG
|
(Sage) [3+binomial(n, 2) for n in range(0, 54)] # Zerinvary Lajos, Mar 12 2009
(PARI) Vec( x*(3-6*x+4*x^2)/(1-x)^3 + O(x^66) ) \\ Joerg Arndt, Jul 24 2013
(GAP) List([1..55], n->3+Binomial(n-1, 2)); # Muniru A Asiru, Oct 28 2018
|
|
CROSSREFS
|
|
|
KEYWORD
|
nonn,easy
|
|
AUTHOR
|
|
|
STATUS
|
approved
|
|
|
|