OFFSET
1,4
COMMENTS
LINKS
Alois P. Heinz, Rows n = 1..150, flattened
FORMULA
G.f. = G(t,z) = Sum_{j>=1}tz^j/(f(j)(f(j)-tzf(j-1))), where the f(j)'s are the Fibonacci polynomials (in z) defined by f(0)=f(1)=1, f(j) = f(j-1) - zf(j-2), j>=2 (Sergi Elizalde).
EXAMPLE
T(4,2)=4 because we have UU(UD)(UD)DD, U(UD)DU(UD)D, U(UD)(UD)DUD and UDU(UD)(UD)D, where U=(1,1), D=(1,-1), with the peaks of maximum height shown between parentheses.
Triangle starts:
1;
1, 1;
3, 1, 1;
8, 4, 1, 1;
23, 12, 5, 1, 1;
71, 36, 17, 6, 1, 1;
...
MAPLE
f[0] := 1: f[1] := 1: for i from 2 to 20 do f[i] := sort(expand(f[i-1]-z*f[i-2])) end do: G := sum(t*z^j/(f[j]*(f[j]-t*z*f[j-1])), j = 1 .. 20): Gser := simplify(series(G, z = 0, 17)): for n to 12 do P[n] := sort(coeff(Gser, z, n)) end do: for n to 12 do seq(coeff(P[n], t, k), k = 1 .. n) end do; # yields sequence in triangular form
CROSSREFS
KEYWORD
nonn,tabl
AUTHOR
Emeric Deutsch, Jan 02 2009
STATUS
approved