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A145507
a(n+1) = a(n)^2 + 2*a(n) - 2 and a(1) = 7.
3
7, 61, 3841, 14760961, 217885999165441, 47474308632322991920487055361, 2253809980117057347661794063813616885861274573005652951041
OFFSET
1,1
COMMENTS
See A145502 for a general formula for a(n+1) = a(n)^2 + 2*a(n) - 2 and a(1) = k-1.
LINKS
FORMULA
From Peter Bala, Nov 12 2012: (Start)
a(n) = alpha^(2^(n-1)) + (1/alpha)^(2^(n-1)) - 1, where alpha = 4 + sqrt(15).
a(n) = 2*A005828(n-1) - 1.
Recurrence: a(n) = 9*(Product_{k = 1..n-1} a(k)) - 2 with a(1) = 7.
Product_{n >= 1} (1 + 1/a(n)) = (3/10)*sqrt(15).
Product_{n >= 1} (1 + 2/(a(n) + 1)) = sqrt(5/3). (End)
MATHEMATICA
aa = {}; k = 7; Do[AppendTo[aa, k]; k = k^2 + 2 k - 2, {n, 1, 10}]; aa
(* Alternative: *)
k = 8; Table[Floor[((k + Sqrt[k^2 - 4])/2)^(2^(n - 1))], {n, 1, 7}]
CROSSREFS
KEYWORD
nonn,changed
AUTHOR
Artur Jasinski, Oct 11 2008
STATUS
approved