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A145510
a(n+1) = a(n)^2 + 2*a(n) - 2 and a(1) = 10.
10
10, 118, 14158, 200477278, 40191139395243838, 1615327685887921300502934267457918, 2609283532796026943395592527806764363779539144932833602430435810558
OFFSET
1,1
COMMENTS
See A145502 for a general formula for a(n+1) = a(n)^2 + 2*a(n) - 2 and a(1) = k-1.
LINKS
FORMULA
From Peter Bala, Nov 12 2012: (Start)
a(n) = alpha^(2^(n-1)) + (1/alpha)^(2^(n-1)) - 1, where alpha = (11 + sqrt(117))/2.
a(n) == 1 (mod 9).
Recurrence: a(n) = 12*(Product_{k = 1..n-1} a(k)) - 2 with a(1) = 10.
Product_{n >= 1} (1 + 1/a(n)) = 12/sqrt(117).
Product_{n >= 1} (1 + 2/(a(n) + 1)) = sqrt(13/9). (End)
MATHEMATICA
aa = {}; k = 10; Do[AppendTo[aa, k]; k = k^2 + 2 k - 2, {n, 1, 10}]; aa
(* or *)
k = 11; Table[Floor[((k + Sqrt[k^2 - 4])/2)^(2^(n - 1))], {n, 1, 6}]
KEYWORD
nonn,easy
AUTHOR
Artur Jasinski, Oct 11 2008
STATUS
approved