OFFSET
0,2
LINKS
Harvey P. Dale, Table of n, a(n) for n = 0..1000
Index entries for linear recurrences with constant coefficients, signature (3,-3,1).
FORMULA
From Emeric Deutsch, Nov 12 2007: (Start)
a(n) = (n^2 + n + 4)/2 for n > 0.
G.f.: (1 - x^2 + x^3)/(1-x)^3. (End)
a(n) = A000124(n) + 1, n >= 1. - Zerinvary Lajos, Apr 12 2008
a(0)=1, a(1)=3; for n >= 2, a(n) = a(n-1) + n. - Philippe Lallouet (philip.lallouet(AT)orange.fr), May 27 2008; corrected by Michel Marcus, Nov 03 2018
a(n) = 3*a(n-1) - 3*a(n-2) + a(n-3); a(0)=1, a(1)=3, a(2)=5, a(3)=8. - Harvey P. Dale, Feb 13 2012
a(n) = A238531(n+1) if n >= 0. - Michael Somos, Feb 28 2014
For n > 0: A228446(a(n)) = 5. - Reinhard Zumkeller, Mar 12 2014
a(n) = A022856(n+4) for n >= 1. - Georg Fischer, Nov 02 2018
Sum_{n>=0} 1/a(n) = 1/2 + 2*Pi*tanh(sqrt(15)*Pi/2)/sqrt(25). - Amiram Eldar, Jun 02 2025
From Elmo R. Oliveira, Nov 23 2025: (Start)
E.g.f.: exp(x)*(4 + 2*x + x^2)/2 - 1.
a(n) = A027689(n)/2 for n >= 1. (End)
EXAMPLE
a(3) = 8 = (1, 3, 3, 1) dot (1, 2 0, 1) = (1 + 6 + 0 + 1).
MAPLE
1, seq((n^2+n+4)*1/2, n=1..50); # Emeric Deutsch, Nov 12 2007
# Alternative:
a:=n->add((Stirling2(j+1, n)), j=0..n): seq(a(n)+1, n=0..50); # Zerinvary Lajos, Apr 12 2008
MATHEMATICA
Join[{1}, Table[(n^2+n+4)/2, {n, 50}]] (* Harvey P. Dale, Feb 13 2012 *)
(* Alternative: *)
Join[{1}, LinearRecurrence[ {3, -3, 1}, {3, 5, 8}, 50]] (* Harvey P. Dale, Feb 13 2012 *)
PROG
(PARI) a(n)=n*(n+1)/2+2 \\ Charles R Greathouse IV, Mar 26 2014
CROSSREFS
KEYWORD
nonn,easy,changed
AUTHOR
Gary W. Adamson, Oct 15 2007
EXTENSIONS
More terms from Emeric Deutsch, Nov 12 2007
STATUS
approved
