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A130128 Triangle read by rows: T(n,k) = (n - k + 1)*2^(k-1). 7
1, 2, 2, 3, 4, 4, 4, 6, 8, 8, 5, 8, 12, 16, 16, 6, 10, 16, 24, 32, 32, 7, 12, 20, 32, 48, 64, 64, 8, 14, 24, 40, 64, 96, 128, 128, 9, 16, 28, 48, 80, 128, 192, 256, 256, 10, 18, 32, 56, 96, 160, 256, 384, 512, 512, 11, 20, 36, 64, 112, 192, 320, 512, 768, 1024, 1024 (list; table; graph; refs; listen; history; text; internal format)
OFFSET
1,2
COMMENTS
T(n,k) is the number of paths from node 0 to odd k in a directed graph with 2n+1 vertices labeled 0, 1, ..., 2n+1 and edges leading from i to i+1 for all i, from i to i+2 for even i, and from i to i-2 for odd i. - Grace Work, Mar 01 2020
LINKS
E. Krom and M. M. Roughan, Path Counting and Eulerian Numbers, Girls' Angle Bulletin, Vol. 13, No. 3 (2020), 8-10.
FORMULA
Equals A004736 * A130123 as infinite lower triangular matrices.
As a square array, n >= 0, k >= 1, read by descending antidiagonals, A(n,k) = k * 2^n. - Peter Munn, Sep 22 2022
G.f.: x*y/( (1-x)^2 * (1-2*x*y) ). - Kevin Ryde, Sep 24 2022
EXAMPLE
First few rows of the triangle are:
1;
2, 2;
3, 4, 4;
4, 6, 8, 8;
5, 8, 12, 16, 16;
6, 10, 16, 24, 32, 32;
7, 12, 20, 32, 48, 64, 64;
...
From Peter Munn, Sep 22 2022: (Start)
As a square array, showing top left:
1, 2, 3, 4, 5, 6, 7, ...
2, 4, 6, 8, 10, 12, 14, ...
4, 8, 12, 16, 20, 24, 28, ...
8, 16, 24, 32, 40, 48, 56, ...
16, 32, 48, 64, 80, 96, 112, ...
32, 64, 96, 128, 160, 192, 224, ...
...
(End)
MATHEMATICA
Table[(n - k + 1)*2^(k - 1), {n, 11}, {k, n}] // Flatten (* Michael De Vlieger, Mar 23 2020 *)
PROG
(PARI) T(n, k)={(n - k + 1)*2^(k-1)} \\ Andrew Howroyd, Mar 01 2020
CROSSREFS
Row sums are A000295.
Cf. A004736, A054582 (subtable of square array), A130123.
Sequence in context: A367410 A259197 A309559 * A210556 A208914 A049980
KEYWORD
nonn,easy,tabl,walk
AUTHOR
Gary W. Adamson, May 11 2007
EXTENSIONS
Name clarified by Grace Work, Mar 01 2020
Terms a(56) and beyond from Andrew Howroyd, Mar 01 2020
STATUS
approved

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Last modified April 19 18:05 EDT 2024. Contains 371798 sequences. (Running on oeis4.)