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A124665
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Numbers that cannot be either prefixed or followed by one digit to form a prime.
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8
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20, 32, 62, 84, 114, 126, 134, 135, 146, 150, 164, 168, 176, 185, 192, 196, 204, 210, 218, 232, 236, 240, 248, 256, 258, 282, 294, 298, 305, 314, 315, 324, 326, 328, 342, 348, 350, 356, 366, 368, 374, 375, 378, 395, 406, 408, 410, 414, 416, 418
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OFFSET
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1,1
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COMMENTS
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Prefixing by 0 gives the number itself, implying that a(n) is not prime.
All integers of the form 100*(21*n)^3 belong to the sequence, so it is infinite. - Mauro Fiorentini, Jan 05 2023
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LINKS
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EXAMPLE
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If you prefix 20 with any digit you will get an even number. Also 201, 203, 207 and 209 are all composite.
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MATHEMATICA
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okQ[n_]:=If[EvenQ[n]||Divisible[n, 5], Union[PrimeQ[10 n+{1, 3, 7, 9}]] == {False}, !PrimeQ[n]&&Union[PrimeQ[10 n+{1, 3, 7, 9}]]=={False} && Union[ PrimeQ[Table[FromDigits[Join[{i}, IntegerDigits[n]]], {i, 9}]]] == {False}]; Select[Range[500], okQ] (* Harvey P. Dale, Jul 15 2011 *)
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PROG
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(PARI) is(n)=my(N=10*n, D=10^#Str(n)); forstep(k=n, n+9*D, D, if(isprime(k), return(0))); !(isprime(N+1)||isprime(N+3)||isprime(N+7)||isprime(N+9)) \\ Charles R Greathouse IV, Jul 15 2011
(Python)
from sympy import isprime
def ok(n):
s = str(n)
if any(isprime(int(s+c)) for c in "1379"): return False
return not any(isprime(int(c+s)) for c in "0123456789")
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CROSSREFS
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KEYWORD
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base,nonn
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AUTHOR
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EXTENSIONS
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STATUS
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approved
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