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A118123
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a(n) = number of k's such that prime(n+1) = prime(n) + (prime(n) mod k).
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4
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0, 0, 1, 0, 2, 1, 3, 2, 1, 3, 1, 2, 3, 2, 1, 1, 3, 2, 4, 3, 1, 4, 3, 3, 2, 5, 4, 7, 6, 2, 2, 2, 7, 2, 5, 2, 1, 2, 3, 1, 3, 3, 7, 6, 7, 2, 1, 2, 8, 7, 1, 3, 5, 4, 1, 1, 3, 2, 6, 5, 5, 3, 2, 3, 2, 2, 4, 2, 7, 6, 1, 6, 2, 1, 6, 3, 2, 2, 2, 5, 3, 2, 7, 3, 6, 3, 6, 2, 7, 6, 5, 2, 6, 5, 10, 3, 2, 3, 2, 2, 2, 3, 1, 9, 2
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OFFSET
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1,5
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LINKS
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FORMULA
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a(n) = # { k>0 | prime(n+1) - prime(n) = prime(n) % k }, where p % k is the remainder of p divided by k.
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MATHEMATICA
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f[n_] := If[n == 1, 0, Block[{p = Prime@n, np = Prime[n + 1]}, Length@Select[Divisors[2p - np], # >= np - p &]]]; Array[f, 105]
nk[n_]:=Count[Mod[n, Range[n-1]], _?(#==NextPrime[n]-n&)]; nk/@Prime[ Range[ 110]] (* Harvey P. Dale, May 27 2016 *)
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PROG
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(PARI) A118123(n)={my(d=prime(n+1)-n=prime(n)); sumdiv(n-d, k, k>d)}
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CROSSREFS
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KEYWORD
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nonn
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AUTHOR
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EXTENSIONS
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STATUS
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approved
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