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A116445
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Array read by antidiagonals: the binomial transform of the sequence (1,2,..n,0,0,0..) in row n.
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3
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1, 1, 1, 1, 3, 1, 1, 3, 5, 1, 1, 3, 8, 7, 1, 1, 3, 8, 16, 9, 1, 1, 3, 8, 20, 27, 11, 1, 1, 3, 8, 20, 43, 41, 13, 1, 1, 3, 8, 20, 48, 81, 58, 15, 1, 1, 3, 8, 20, 48, 106, 138, 78, 17, 1, 1, 3, 8, 20, 48, 112, 213, 218, 101, 19, 1
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OFFSET
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1,5
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COMMENTS
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Create an array by rows: (binomial transforms of 1,0,0,0,...; 1,2,0,0,0,...; 1,2,3,0,0,0,...; etc.). Antidiagonals of the array become rows of the triangle.
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LINKS
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EXAMPLE
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First few rows of the array:
1, 1, 1, 1, 1, 1, 1, 1, 1, 1, ...
1, 3, 5, 7, 9, 11, 13, 15, 17, ...
1, 3, 8, 16, 27, 41, 58, 78, 101, ... A104249
1, 3, 8, 20, 43, 81, 138, 218, ... A139488
1, 3, 8, 20, 48, 106, 213, ...
1, 3, 8, 20, 48, 112, 249, ...
...
Diagonals converge to A001792, binomial transform of (1,2,3,...); and the first few rows of the triangle created by reading upwards antidiagonals are:
1
1, 1;
1, 3, 1;
1, 3, 5, 1;
1, 3, 8, 7, 1;
1, 3, 8, 16, 9, 1;
1, 3, 8, 20, 27, 22, 1;
...
a(4), a(5), a(6) = 1, 3, 1 = antidiagonals of the array becoming row three of the triangle.
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MAPLE
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local a, i ;
a := 0 ;
for i from 0 to n do
a := a+binomial(k, i)*(i+1) ;
end do:
a ;
end proc:
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CROSSREFS
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KEYWORD
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AUTHOR
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EXTENSIONS
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STATUS
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approved
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