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A107980
Triangle read by rows: T(n,k) = (n+2)*(k+1)*(k+2)*(2*n-k+2)*(2*n-k+3)/24.
1
1, 5, 9, 14, 30, 40, 30, 70, 105, 125, 55, 135, 216, 280, 315, 91, 231, 385, 525, 630, 686, 140, 364, 624, 880, 1100, 1260, 1344, 204, 540, 945, 1365, 1755, 2079, 2310, 2430, 285, 765, 1360, 2000, 2625, 3185, 3640, 3960, 4125, 385, 1045, 1881, 2805, 3740, 4620, 5390, 6006, 6435, 6655
OFFSET
0,2
COMMENTS
Kekulé numbers for certain benzenoids.
REFERENCES
S. J. Cyvin and I. Gutman, Kekulé structures in benzenoid hydrocarbons, Lecture Notes in Chemistry, No. 46, Springer, New York, 1988 (p. 237, K{B(n,3,l)}).
FORMULA
T(n, k) = (n+2)*(k+1)*(k+2)*(2*n-k+2)*(2*n-k+3)/24.
T(n, 0) = A000330(n+1).
T(n, n) = A006414(n).
Sum_{k=0..n} T(n, k) = A006858(n+1).
T(n, n-1) = 5*binomial(n+4, 5) = 5*A000389(n+4). - G. C. Greubel, Dec 14 2021
EXAMPLE
Triangle begins:
1;
5, 9;
14, 30, 40;
30, 70, 105, 125;
55, 135, 216, 280, 315;
91, 231, 385, 525, 630, 686;
140, 364, 624, 880, 1100, 1260, 1344;
204, 540, 945, 1365, 1755, 2079, 2310, 2430;
285, 765, 1360, 2000, 2625, 3185, 3640, 3960, 4125;
385, 1045, 1881, 2805, 3740, 4620, 5390, 6006, 6435, 6655;
506, 1386, 2520, 3800, 5130, 6426, 7616, 8640, 9450, 10010, 10296;
MAPLE
T:=proc(n, k) if k<=n then 1/24*(n+2)*(k+1)*(k+2)*(2*n-k+2)*(2*n-k+3) else 0 fi end: for n from 0 to 9 do seq(T(n, k), k=0..n) od; # yields sequence in triangular form
MATHEMATICA
T[n_, k_]:= (1/6)*(n+2)*Binomial[k+2, 2]*Binomial[2*n-k+3, 2];
Table[T[n, k], {n, 0, 15}, {k, 0, n}]//Flatten (* G. C. Greubel, Dec 14 2021 *)
PROG
(Sage)
def A107980(n, k): return (n+2)*(k+1)*(k+2)*(2*n-k+2)*(2*n-k+3)/24
flatten([[A107980(n, k) for k in (0..n)] for n in (0..15)]) # G. C. Greubel, Dec 14 2021
CROSSREFS
KEYWORD
nonn,tabl
AUTHOR
Emeric Deutsch, Jun 12 2005
STATUS
approved