
COMMENTS

Take the sequence of natural numbers: s0=1,2,3,4,5,6,7,8,9,10,11, Repeating the procedure: "Move the first term s(1) after s(1)th prime": we get successively: s1=2,1,3,4,5,6,7,8,9,10,11, s2=1,3,2,4,5,6,7,8,9,10,11, s3=3,2,1,4,5,6,7,8,9,10,11, s4=2,1,4,5,3,6,7,8,9,10,11, s5=1,4,5,3,2,6,7,8,9,10,11, ............................................................ s100=8,68,69,70,71,20,72,73,21,74,75,76,77,78,79,22,80,81,82, 83,23,9,84,85,86,87,88,89,24,90,91,92,93,94,95,96,97,25,98,99, 100,101,26,102,103,27,104,105,106,107,28,108,109,29,10,110, The sequence A104741 gives the first terms in the rearrangements s0,s1,s2,... Cf. A104705, A104706, A104717
