OFFSET
0,3
COMMENTS
a(2^n-1)=(-1)^n.
FORMULA
a(n)=sum{k=0..floor(n/2), (-1)^A010060(n-2k)*mod(binomial(n-k, k), 2)10^k}
CROSSREFS
KEYWORD
easy,sign
AUTHOR
Paul Barry, Dec 11 2004
STATUS
approved