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A100737
Inverse modulo 2 binomial transform of 4^n.
0
1, 3, 15, 45, 255, 765, 3825, 11475, 65535, 196605, 983025, 2949075, 16711425, 50134275, 250671375, 752014125, 4294967295, 12884901885, 64424509425, 193273528275, 1095216660225, 3285649980675, 16428249903375, 49284749710125
OFFSET
0,2
COMMENTS
4^n may be retrieved as sum{k=0..n, mod(binomial(n,k),2)*a(k)}.
FORMULA
a(n)=sum{k=0..n, (-1)^A010060(n-k)*mod(binomial(n, k), 2)4^k}.
CROSSREFS
Sequence in context: A260021 A005560 A100747 * A178669 A110464 A261505
KEYWORD
easy,nonn
AUTHOR
Paul Barry, Dec 06 2004
STATUS
approved