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 A096378 Floor of area of triangle with consecutive integer sides. 2
 0, 2, 6, 9, 14, 20, 26, 34, 42, 51, 61, 72, 84, 96, 109, 124, 139, 155, 172, 190, 208, 228, 248, 269, 291, 314, 338, 363, 388, 415, 442, 470, 499, 529, 560, 591, 624, 657, 691, 727, 762, 799, 837, 875, 915, 955, 996, 1038, 1081, 1125, 1170, 1215, 1261, 1308 (list; graph; refs; listen; history; text; internal format)
 OFFSET 1,2 LINKS Robert Israel, Table of n, a(n) for n = 1..10000 FORMULA Given a triangle ABC with sides a, b, base c, height h and x=base of right triangle formed by a and h. Then a^2 = h^2 + x^2, b^2 = h^2 + (c-x)^2, h = sqrt(a^2 - x^2), area = (1/2)hc. Hence x = (a^2 - b^2 + c^2)/2c and so area = (1/4)*sqrt(4*a^2*c^2 - (a^2 - b^2 + c^2)^2). From Robert Israel, Jan 16 2018: (Start) a(n) = floor((n+1)*sqrt(3*(n+3)*(n-1))/4). sqrt(3)*(n^2/4 + n/2) - 2 < a(n) < sqrt(3)*(n^2/4 + n/2). (End) EXAMPLE For triangle with sides 3,4,5 area = (1/4)*sqrt(4*9*25 - (9-16+25)^2) = 6. This is the 3,4,5 right triangle with base 3 and height 4. (1/2)*3*4 = 6. MAPLE f:= n -> floor((n+1)*sqrt(3*(n+3)*(n-1))/4): map(f, [\$1..100]); # Robert Israel, Jan 16 2018 PROG (PARI) area(n) = { for(x=1, n, a=x; b=x+1; c=x+2; z=1/4*sqrt(4*a^2*c^2-(c^2+a^2-b^2)^2); print1(floor(z)", ") ) } CROSSREFS Sequence in context: A184824 A184836 A327895 * A342426 A217001 A320666 Adjacent sequences:  A096375 A096376 A096377 * A096379 A096380 A096381 KEYWORD nonn AUTHOR Cino Hilliard, Aug 04 2004 STATUS approved

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Last modified November 29 21:32 EST 2021. Contains 349416 sequences. (Running on oeis4.)