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A093987
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a(1) = 1, a(2) = 2, a(n+1) = a(n)^(2n)/ a(n-1). Symmetrically a(n) = {a(n-1)*a(n+1)}^[1/{(n-1) +(n+1)}].
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0
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OFFSET
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1,2
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COMMENTS
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LINKS
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EXAMPLE
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a(5) = 8388608^8/16 = 1.53249554e+54.
a(6) =~ 8.5173068734e+534.
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MATHEMATICA
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a[1] = 1; a[2] = 2; a[n_] := a[n - 1]^(2n - 2)/a[n - 2]; Table[ a[n], {n, 6}] (* Robert G. Wilson v, May 24 2004 *)
RecurrenceTable[{a[1]==1, a[2]==2, a[n+1]==a[n]^(2n)/a[n-1]}, a, {n, 5}] (* Harvey P. Dale, Jan 31 2020 *)
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CROSSREFS
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KEYWORD
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nonn
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AUTHOR
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EXTENSIONS
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STATUS
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approved
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